The following was jacked from an email I received.

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Kinetic Energy Released

Wow, it's almost like we're an educational site lately, what with all this physics and shi'yat. Anyway, here's a neat video from the gun camera of an AH-64 Apache attack in Iraq. Now while we don't know who these unlucky bastards were, I can tell you the guy in the middle of the road gets fucked up. As I noticed his white image on the infrared get bigger and bigger as his innards are scattered, I sat wondering, "just how fucked up was he?" And so, let the physics begin...

Taking our queue from Stupid Movie Physics, we know the formula for kinetic energy is <missing text>

So in their example, a small .45 caliber bullet weighing 15 grams and traveling at 288 meters per second yields is 619 joules of energy. They further explain that if a man weighing 139 lbs (63.2 kg) were to fall off of a bed, it would yield roughly the same energy as being shot by that bullet; the difference being with a fall the energy is dispersed through the entire surface area of the man's body versus a bullet where the focal point is a tiny circle.

KE = ½mass x velocity2

KE = (.015kg / 2) x (288 m/s x 288 m/s)

KE = 619 joules of energy

PE = mass x gravity x height

PE = 63.2kg x 9.81 m/s x 1 meter

PE = 619 joules of energy

So taking this information, let's plug in the numbers of the Apache's M230 automatic gun ammunition. We have each round weighing 350 grams and traveling at 800 meters per second.

KE = (.3505kg / 2) x (800 m/s x 800 m/s)

KE = .175 x 640,000

KE = 112,160 joules of ass whoopin

Now that's a little hard to wrap your army around... I mean just how much energy is 112,000 joules? Well, for starters it's 180 times the energy of the .45 caliber handgun bullet. So imagine 180 people all pointing guns at this guy's body and everyone pulling the trigger all at the same time. Hmmm, yes...messy.

Furthermore, we can calculate just how high up this guy would have to plunge in order to release the same amount of energy as was released when he caught one of the Apache's 30mm rounds square in the chest...

112,160 = 63.2kg x 9.81 x height

height = 112,160 / (63.2 x 9.81)

height = 112,160 / 619.99

height = 180.9 meters (or 593 feet)

Now, taking our queue from the evolution of skyscrapers, I found an average 4.26 meters (13.96 feet) per foot. Thus this poor bastard you see splattered all over Main Street in downtown Baghdad? He looks the same as if someone tossed his happy ass off a 42 story building.

And the best part? The Apache's 30mm gun is really a popgun compared to the 30mm gun of an A-10 -- same diameter slugs but they're much heavier and travel much faster. So should you be unlucky enough to eat one of the Warthog's tank killing depleted uranium slugs...

KE = (.91kg / 2) x (1500 m/s x 1500 m/s) = 1,023,750 joules of smackdown

1,023,750 joules / 619 joules per .45 cal bullet = 1,626 people shooting you at once

1,023,750 joules = 63.2kg x 9.81 x height

height = 1,651 meters or 5,417 feet or a 1.02 mile freefall

But at a fire rate of 3,900 rounds per minute, the A-10's bullets will be more like Lays potato chips -- nobody gonna eat just one. All you fuckers better keep that in mind when you hear the whoop-whoop-whoop of helicopter blades, eh?